Using replace() with variable

Hi, I would like to replace URLs in my markdown with a value composed by the literal strin I’ve provided as 1st parameter augmented with the content of a variable.
Which is the correct syntax?
I’ve tried this :

@xmasrock

Current limitation of variable system is that it can’t nest variables inside function parameters.
So I am not sure if this is achievable at the moment.

So you’ll have for this part to manually write the endpoint in replace function.

OK, understand. Thanks @dejan